2+3x^2+20x^4=0

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Solution for 2+3x^2+20x^4=0 equation:


Simplifying
2 + 3x2 + 20x4 = 0

Solving
2 + 3x2 + 20x4 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
20 the coefficient of the squared term: 

Divide each side by '20'.
0.1 + 0.15x2 + x4 = 0

Move the constant term to the right:

Add '-0.1' to each side of the equation.
0.1 + 0.15x2 + -0.1 + x4 = 0 + -0.1

Reorder the terms:
0.1 + -0.1 + 0.15x2 + x4 = 0 + -0.1

Combine like terms: 0.1 + -0.1 = 0.0
0.0 + 0.15x2 + x4 = 0 + -0.1
0.15x2 + x4 = 0 + -0.1

Combine like terms: 0 + -0.1 = -0.1
0.15x2 + x4 = -0.1

The x term is 0.15x2.  Take half its coefficient (0.075).
Square it (0.005625) and add it to both sides.

Add '0.005625' to each side of the equation.
0.15x2 + 0.005625 + x4 = -0.1 + 0.005625

Reorder the terms:
0.005625 + 0.15x2 + x4 = -0.1 + 0.005625

Combine like terms: -0.1 + 0.005625 = -0.094375
0.005625 + 0.15x2 + x4 = -0.094375

Factor a perfect square on the left side:
(x2 + 0.075)(x2 + 0.075) = -0.094375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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